
HFIT-565
Assessment & Evaluation
of Health Fitness Parameters
Fall Semester 2008
Dr. Marc Schaeffer
mschaef@american.edu
Lecture Notes Class #10
Thursday October 30, 2008

Go to Course Syllabus
Topics for Discussion
Assignment #9 due (solutions)
- Sample problem to introduce the general method of solving
intervals about sample proportions
- Introduction to Proportion Confidence Intervals CI
- Things you should not say about your CI
- Dealing with Margin of Error (ME)
- introduction to c2 (this is in the next lecture)
- there is a quiz at the end of our class today (click
here to see key)
Lecture #9
Lecture #11
Brief overview of the page 486 Sea Fan problem
- 51.9% (54/104) of random sample of sea fans
on the Las Redes Reef are infected
- do you suppose a second random sample would contain
51.9% infection? Why?
- so, what can we say about sea fans at this location based
on this 51.9% infection?
Some Important details
- if we do NOT know p, we cannot find the true
standard deviation sigma
- thus, we use phat AND we find the standard
error (SE)
- how is the SE calculated -- SE = sqrt(pq
÷ n)
- in this sea fan problem the SE = 4.9% [sqrt (0.519
* 0.481)/104]
- we could go on and say that for phat = 51.9%,
that 68% of the sample phats fall within 51.9% ± 4.9% WHY?
- also, for phat = 51.9%, that 95% of the sample
phats fall within 51.9% ± 2*4.9% WHY?
Four statements we should NOT state about the infected
sea fan CI
- 51.9% of all sea fans on the Las Redes Reef are infected
- we do not have enough information to say this
- It is probably true that 51.9% of all sea fans on the Las
Redes Reef are infected
- in fact, this is probably NOT true that 51.9% is the
true proportion of infected fans
- We do not know exactly what proportion of sea fans on the
Las Redes Reef are infected, but we know that is within the
interval of 51.9% ± 2*4.9%, i.e., 42.1 and 61.7%
- we cannot know for sure
that the true proportion is in this range or any particular range
- we do not know exactly what proportion of
sea fans on the Las Redes Reef are infected, but the interval from 42.1%
and 61.7% probably contains the true proportion
- as the book says, this statement is the most defensible
of this four but it can be made more accurate with subtle rewording.
Now we get to what you really need to concentrate on
- we are 95% confident that between 42.1 and 61.7%
of the Las Redes sea fans are infected
- this is good statement representing a confidence
interval
Margin of Error (ME)
- What is ME - the extent of the interval
on either side of phat
- in the above sea fan example, the ME of our
95% CI is 2 SE - WHY?
- the ME of a 99.7 CI would be what?
- which CI is a longer interval - a 95% CI or a 99.7% CI?
WHY?
- the book represents this issue as being certainty vs. precision;
WHY?
- What are the most common CIs in use?
- What are the critical values associated with these CIs?
BACK TO TOP
Assignment #10,
Due prior to class 11/6/08
Text Reading & Text Problems
Read De Veaux Chapters 19, 20, 21, 22, 23
Problems Chapter 19: 2, 4, 5, 8, 19, 20, 24, 26
Solutions
BACK TO TOP
Go to Lecture #11 ----->
<------ Go to Lecture #9
Go to Course Syllabus
send email to Dr.
Schaeffer


this page last modified by M Schaeffer
- on November 6, 2008